(2x^3+3x^2-x+2)+(x^4-x^3+3x^2+4x+2)=0

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Solution for (2x^3+3x^2-x+2)+(x^4-x^3+3x^2+4x+2)=0 equation: 


Simplifying
(2x3 + 3x2 + -1x + 2) + (x4 + -1x3 + 3x2 + 4x + 2) = 0

Reorder the terms:
(2 + -1x + 3x2 + 2x3) + (x4 + -1x3 + 3x2 + 4x + 2) = 0

Remove parenthesis around (2 + -1x + 3x2 + 2x3)
2 + -1x + 3x2 + 2x3 + (x4 + -1x3 + 3x2 + 4x + 2) = 0

Reorder the terms:
2 + -1x + 3x2 + 2x3 + (2 + 4x + 3x2 + -1x3 + x4) = 0

Remove parenthesis around (2 + 4x + 3x2 + -1x3 + x4)
2 + -1x + 3x2 + 2x3 + 2 + 4x + 3x2 + -1x3 + x4 = 0

Reorder the terms:
2 + 2 + -1x + 4x + 3x2 + 3x2 + 2x3 + -1x3 + x4 = 0

Combine like terms: 2 + 2 = 4
4 + -1x + 4x + 3x2 + 3x2 + 2x3 + -1x3 + x4 = 0

Combine like terms: -1x + 4x = 3x
4 + 3x + 3x2 + 3x2 + 2x3 + -1x3 + x4 = 0

Combine like terms: 3x2 + 3x2 = 6x2
4 + 3x + 6x2 + 2x3 + -1x3 + x4 = 0

Combine like terms: 2x3 + -1x3 = 1x3
4 + 3x + 6x2 + 1x3 + x4 = 0

Solving
4 + 3x + 6x2 + 1x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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